Leet code刷題筆記

Reverse Integer -Python解題

困難度:Easy

題目: 簡單來說呢!就是將數字位置反轉。

Given a signed 32-bit integer x, return x with its digits reversed. If reversing x causes the value to go outside the signed 32-bit integer range [-231, 231 - 1], then return 0.

Assume the environment does not allow you to store 64-bit integers (signed or unsigned).

Constraints:

-231 <= x <= 231 - 1

Example 1:

Input: x = 123

Output: 321

Example 2:

Input: x = -123

Output: -321

Example 3:

Input: x = 120

Output: 21

Example 4:

Input: x = 0

Output: 0

Python解題筆記

Inline code has back-ticks around it.

class Solution:
    def reverse(self, x):
        num=0
        a=abs(x)
        while(a != 0):
            temp = a % 10 
            num =num * 10 + temp
            a=int(a/10)
        if x>0 and num <2147483647:
            return num
        elif x < 0 and num <= 2147483647:
            return -num
        else:
            return 0
        

題目原處-LeetCode